Question

Factorise: 12x-8+3xy-2y

(4+y) (3x-2)

(4-y) (3x+2)

both

none of these

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Answer 1

Step-by-step explanation:

12x−8+3xy−2y

Do the grouping 12x−8+3xy−2y=(12x−8)+(3xy−2y), and factor out 4 in the first and y in the second group.

4(3x−2)+y(3x−2)

Factor out common term 3x−2 by using distributive property.

(3x−2)(4+y)

Answer 2

Answer:

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