Math, asked by itzkanika85, 3 months ago

Factorise 12x+y^2-z^2-6xy+20yz-6zx​

Answers

Answered by Anonymous
33

\tt =12x+y²-z²-6xy+20yz-6zx

\tt =x=\sqrt{x} \: factorise−12x+y²−z²

\tt =−6xy+20yz−6xy \: formula \: −x^{3}

\tt =−y^{3} −z ^{3}−3xyz=(x+y+z)(x^{2})

\tt =+y ^{2}+z^{2}−xy−yz−xz)x=x

Answered by AbhinavRocks10
8

\rm=12x+y²-z²-6xy+20yz-6zx=12x+y²−z²−6xy+20yz−6zx

\rm=x=\sqrt{x} \: Factorise−12x+y²−z²=x= 3

\rm =−6xy+20yz−6xy \: Formula \: −x^{3}

\rm =−y^{3} −z ^{3}−3xyz=(x+y+z)(x^{2})=−y^3 −z^ 3 −3xyz=(x+y+z)(x^ 2 )

\rm =+y ^{2}+z^{2}−xy−yz−xz)x=x=+y^2 +z^2 −xy−yz−xz)x=x

MORE INFORMATION -:

The polynomial cannot be factored using the grouping method. Try a different method, or if you aren't sure, choose Factor.The polynomial cannot be factored using the grouping method.

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