Question

Factorise 12x² + 27x + 6 in the form of (ax+3) (cx+2) by using the method of splitting the middle term and find the values of a and c ???​

Answer 1

Answer:

a = 12, c = 1

Step-by-step explanation:

12x² + 27x + 6

= 12x² + (24+3)x + 6

= 12x² + 24x + 3x + 6

= 12x(x+2) + 3(x+2)

= (12x+3)(x+2)

According to the question: 12x² + 27x + 6 = (ax+3) (cx+2)

So, (ax+3) (cx+2) = (12x+3)(x+2)

=> a = 12, c = 1

Answer 2

Given,

Factorize $12x^{2} +27x+6$

We have factorize the given equation in the form of $(ax+3)(cx+2)$ by using method of splitting the middle term

We have to find the $a$ and $c$ values of factors

First we have to split the middle term of equation

$27x= 24x+3x$

$12x^{2} +24x+3x+6$

$= 12x(x+2)+3(x+2)$

$= (12x+3)(x+2)$

The values of $a$ and $c$ is

$a= 12$ and $c =1$

Therefore, the values of $a$ and $b$ is $12$ and $1$.