Question

factorise 12x³+ 4x²-3x-1

$by \: putting \: value \: of \: x \: so \: that \: the \: Answer \: will \: be \: 0$
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Answer 1

$12 {x}^{3} + 4 {x}^{2} - 3x - 1 \\ \\ 4 {x}^{2} (3x + 1) - 1(3x + 1) \\ \\ (3x + 1)(4 {x}^{2} - 1)$

By trial and error method

let the value of x be 0

$(3x + 1)(4 {x}^{2} - 1) \\ put \: x \: = 0 \\ (3 \times 0 + 1)(4 \times {0}^{2} - 1) \\ + 1 - 1 \\ 0$

the value of x can be 0