Question

factorise:
12xpowe2-7x+1​

Answer 1

Solution

$12 {x}^{2} - 7x + 1 = 0 \\ \\ 12 {x}^{2} - 4x - 3x + 1 = 0 \\ \\ 4x(3x - 1) - 1(3x - 1) = 0 \\ \\ (4x - 1)(3x - 1) = 0$

Answer 2

Answer:

( 3 x - 1 ) ( 4 x - 1 )

Step-by-step explanation:

$12x^{2}-7x+1\\\\=>12x^{2}-4x-3x+1\\\\=>4x(3x-1)-(3x-1)\\\\=>(3x-1)(4x-1)$

Here The factors 3 and 4 is suitable for 12

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