Question

Factorise: 12xy(9x²-16y²)÷4xy(3x+4y​

Answer 1

12xy(9x²–16y²)÷4xy(3x+4y)

$\frac{12xy(9 {x}^{2} - 16 {y}^{2} }{4y(3x + 4y)}$

$3((3x {)}^{2} - (4y {)}^{2} ) = \frac{3(3x + 4y)(3x - 4y)}{3x +4y }$

=>3(3x–4y)

=9x–12y