Question

factorise 12y^2– y – 6

Answer 1

Step-by-step explanation:

$\huge\red{\mathfrak{ Answer }}$

12y^2-y-6

= 12y^2-9y+8y-6

= 3y(4y-3)+2(4y-3)

= (4y-3)(3y+2)

hope it helps ✌

Answer 2

Answer:

(3y-2)(4y-3)

Step-by-step explanation:

let p(x) = 12y^2 - y - 6                                          

           = 12y^2 - 9y + 8y - 6                                (I took (-Y) as (-9y+8y) becoz

                                                                            -9y*8y= 12* -6= 72 & -9y+8y= y)

= 3y(4y-3) - 2(4y-3)

= (3y-2)(4y-3)

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