Question

factorise 14(s-t)-21(s-t)​

Answer 1

$\textbf{Given:}$

$\mathsf{14(s-t)-21(s-t)}$

$\textbf{To find:}$

$\textsf{Factors of 14(s-t)-21(s-t)}$

$\textbf{Solution:}$

$\textbf{Concept used:}$

$\boxed{\begin{minipage}{8cm} \textsf{The method of writing a polynomial into product of}\\\\\textsf{its factors is called factorization} \end{minipage}}$

$\mathsf{Consider,}$

$\mathsf{14(s-t)-21(s-t)}$

$\mathsf{By\;taking\;s-t\;as\;common}$

$\mathsf{=(s-t)(14-21)}$

$\mathsf{=(s-t)(-7)}$

$\mathsf{=7(-(s-t))}$

$\mathsf{=7(-s+t)}$

$\mathsf{=7(t-s)}$

$\therefore\mathsf{Factors\;of\;the\;given\;polynomial\;are\;7\;and\;t-s}$

$\textbf{Find more:}$

Answer 2

Answer:

7(t-s)

Step-by-step explanation:

14(s-t)-21(s-t)

(s-t) (14-21)

(s-t) (-7)

7(-(s-t)

7(-s+t)

7(t-s)