Question

Factorise:
14p (a – 3b)² – 21p (a – 3b)​

Answer 1

Answer:

please mark me brainiest

Step-by-step explanation:

14(a−3b)3−21p(a−3b)

Take out common in all terms,

Then,7(a−3b)[2(a−3b)2−3p]

Therefore, HCF of 14(a−3b)3 and 21p(a−3b) is 7(a−3b).