Question

factorise : 14x^2y + 21y^2

Answer 1

Answer:

Factorise the following 14x^3+21x^4y-28x^2y^2

Step-by-step explanation:

Step by Step Solution:

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STEP

1

:

Equation at the end of step 1

((14•(x3))+((21•(x4))•y))-((22•7x2)•y2)

STEP

2

1. :

Equation at the end of step

2

:

((14 • (x3)) + ((3•7x4) • y)) - (22•7x2y2)

STEP

3

:

Equation at the end of step

3

:

((2•7x3) + (3•7x4y)) - (22•7x2y2)

STEP

4

:

STEP

5

:

Pulling out like terms

5.1 Pull out like factors :

21x4y + 14x3 - 28x2y2 = 7x2 • (3x2y + 2x - 4y2)

Trying to factor a multi variable polynomial :

5.2 Factoring 3x2y + 2x - 4y2

Try to factor this multi-variable trinomial using trial and error

Factorization fails

Final result :

7x2 • (3x2y + 2x - 4y2)