Question

factorise : 14x^2y^3-21x^4y
please solve this step by step
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Answer 1

Answer:

$14 {x}^{2} {y}^{3} - 21 {x}^{4} y \\ = 7 {x}^{2} y(2 {y}^{2} - 3 {x}^{2} ) \\ = 7 {x}^{2} y( \sqrt{2} y - \sqrt{3} x)( \sqrt{2}y + \sqrt{3} x)$