Factorise:14x³-57x²y-27xy²
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1
27x
3
+y
3
+z
3
−9xyz
=(3x)
3
+y
3
+z
3
−3×(3x)×y×z
=[3x+y+z][(3x)
2
+y
2
+z
2
−(3x)×y−y×z−z(3x)] [Since a
3
+b
3
+c
3
−3abc=(a+b+c)(a
2
+b
2
+c
2
−ab−bc−ca)]
=[3x+y+z][9x
2
+y
2
+z
2
−3xy−yz−3zx]
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