Question

factorise 16 (2p-3q)^2-4 (2p-3q)

Answer 1

16(2p-3q)2-4(2p-3q)
=4(2p-3q){4(2p-3q)-1}
=4(2p-3q)(8p-12q-1)

Answer 2

Hi ,

16(2p - 3q )² - 4 ( 2p - 3q )

= 4× 4 ( 2p - 3q ) ( 2p - 3q ) - 1×4(2p -3q )

= 4( 2p - 3q ) [ 4( 2p - 3q ) - 1 ]

= 4( 2p - 3q ) [ 8p - 12q - 1 ]

I hope this helps you.

:)