Question

Factorise 16+56x+49x^2

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Answer 1

Step-by-step explanation:

$49 {x}^{2} + 56x + 16 = 0 \\ \\ roots \: are \: ...... \\ \\ \frac{ - b \binom{ + }{ - } \sqrt{ {b}^{2} - 4ac} }{2a} \\ \\ \frac{ - 56 \binom{ + }{ - } \sqrt{ {56}^{2} - 4(49)(16)} }{2(49)} \\ \\ \frac{ - 56 \binom{ + }{ - } \sqrt{3136 - 3136} }{98} \\ \\ \frac{ - 56 \binom{ + }{ - } \sqrt{0} }{98} \\ \\ \frac{ - 56}{98} \\ \\ = \frac{ - 8}{14} \\ \\ = \frac{ - 4}{7}$

OR

49x^2 + 56x + 16=0

49x^2 + 28x + 28x + 16 = 0

7x (7x +4) + 4(7x + 4)=0

(7x +4)(7x +4)=0

x = -4/7 , -4/7..

Answer 2

Answer:

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