Question

factorise 16(a+b)^2-4a-4b by grouping method

Answer 1

this may help u........

Answer 2

Answer:4(a+b)[4(a+b)-1]

Step-by-step explanation:[16(a+b)^2]-(4a+4b)

16(a+b)^2-4(a+b)

16(a+b)(a+b)-4(a+b)

(a+b)[16(a+b)-4]

4(a+b)[4(a+b)-1]