Question

factorise 16 C ^2 - (2A + 3 b ^2)​

Answer 1

Answer:

-(2a+3b-4c)(2a+3b+4c)

Step-by-step explanation:

16c²-(2a+3b)²

using identity a²-b²=(a+b)(a-b)

=(4c)²-(2a+3b)²

= {4c+(2a+3b)} {4c-(2a+3b)}

= (4c+2a+3b) (4c-2a-3b)

= -(2a+3b-4c) (2a+3b+4c) is the answer