Question

factorise 16(x+3y)²+24(x+3y)(p+q)+9(p+q)².​

Answer 1

To Factorise -

$\sf{ 16 { ( x + 3y ) } ^ 2 + 24( x + 3y )( p + q ) + 9 { ( p + q ) }^2 }$

Solution -

Let us assume that -

( x + 3y ) = a

( p + q ) = b

So,

$\sf{ 16 { ( x + 3y ) } ^ 2 + 24( x + 3y )( p + q ) + 9 { ( p + q ) }^2 }$

This can be simplified :

$\sf{ 16 a^2 + 24ab + 9 b^2 }$

This is of the form ( a + b )²

So it can be written as -

$\sf{ { (4a + 3b) } ^ 2 }$

Now substituting the values of a -

4 a + 3b

=> 4x + 12y + 3p + 3q

Answer -

$\sf{ { ( 4x + 12y + 3p + 3q ) } ^ 2 }$

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Answer 2

Answer:

(4 (x+3y)+3 (p+q))^2 this is also