Question

factorise:-169a^2-52ab+4b^2
please help me fast tomorrow is my exam

Answer 1

We are given,

169a² - 52ab + 4b²

We can write 169a² as (13a)²

4b² = (2b)²

and 52ab = -2(2b)(13a) right?

So now we have to factorise

(13a)² - 2(13a)(2b) + (2b)²

Can we apply a² - 2ab + b² = (a - b)² ?

Yep so now,

(13a)² - 2(13a)(2b) + (2b)²

= (13a - 2b)²

Hope it helps dear friend ☺️✌️

Answer 2

$hey \: \: mate \: \: your \: \: answer \: \: is \: \: here \: \: \\ = 169 {a}^{2} - 52ab + 4 {b}^{2} \\ = ({13a})^{2} + ({2b})^{2} - 2 \times 13a \times 2b \\ = ( {13a - 2b})^{2} \\ i \: hope \: it \: can \: helpfull.$