Question

factorise 16a^2+4a+1/4

Answer 1

Step-by-step explanation:

16a² + 4a + 1/4

( 4a) ² + ( 1/2)² + 4a

( 4a + 1/2)² - 2.4a.1/2 + 4a

( 4a + 1/2)² - 4a + 4a

( 4a + 1/2)² answer

Answer 2

$Given \: polynomial \: 16a^{2} + 4a + \frac{1}{4} \\= (4a)^{2} + 2 \times (4a) \times + \big(\frac{1}{2}\big)^{2} \\= ( 4a + \frac{1}{2} )^{2}$

/* By Algebraic Identity :

$\boxed { \pink { x^{2} + 2xy + y^{2} = (x+y)^{2} }}$

$= ( 4a + \frac{1}{2} )( 4a + \frac{1}{2} )$

Therefore.,

$\red { Factors \:of \: 16a^{2} + 4a + \frac{1}{4} } \\\green { = ( 4a + \frac{1}{2} )( 4a + \frac{1}{2} )}$

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