FACTORISE:
16a^2 + 4b^2+9c^2- 16ab+12bc - 34ac
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By using (a+b+c)^2= a^2+b^2+c^2+2ab+2bc+2ca
We get,
Root 16a^2 +Root4b^2+Root9c^2
(because in the question the squares of 4a,2b,3c are solved and is given 16a^2,4b^2 and 9c^2)
(4a+2b+3c)
(because powers are equal; so taken as common power)
We get,
Root 16a^2 +Root4b^2+Root9c^2
(because in the question the squares of 4a,2b,3c are solved and is given 16a^2,4b^2 and 9c^2)
(4a+2b+3c)
(because powers are equal; so taken as common power)
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