Math, asked by kritikaroy, 1 year ago

Factorise 16a^2b - 64b^3

Answers

Answered by Anonymous
18

16a^b - 64b^3
16b [a^2 - 4b^2]
16b [a^2 -(2b)^2 ]
16b [ (a+2b) (a-2b)]

Answered by Sudhir1188
27

ANSWER:

  • Factorisation of the above expression is 16b(a+2b)(a-2b)

GIVEN:

  • P(x) = 16a²b-64b³

TO FIND:

  • Factorisation of the above expression.

SOLUTION:

= 16a²b-64b³

= 16b(a²-4b²)

= 16b[(a)²-(2b)²]

= 16b(a+2b)(a-2b)

Factorisation of the above expression is 16b(a+2b)(a-2b)

NOTE:

Some important formulas:

(a+b)² = a²+b²+2ab

(a-b)² = a²+b²-2ab

(a+b)(a-b) = a²-b²

(a+b)³ = a³+b³+3ab(a+b)

(a-b)³ = a³-b³-3ab(a-b)

a³+b³ = (a+b)(a²+b²-ab)

a³-b³ = (a-b)(a²+b²+ab)

(a+b)² = (a-b)²+4ab

(a-b)² = (a+b)²-4ab

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