Math, asked by Yuvikabisla, 1 year ago

Factorise 16a^2b - b ÷ 16a^2 ?


Yuvikabisla: Nope, these are two different terms .....

Answers

Answered by 1212anubhav
27
16a^2 b - b/16a^2
b(16a^2 - 1/16a^2)
b[ (4a)^2 - (1/4a)^2]
b(4a +1/4a) (4a - 1/4a)
Answered by vishalsaini
16

 {16a}^{2} b -b \div  {16a}^{2}   \\  {16a}^{2} b -  \frac{b}{16}  \times  {a}^{2}  \\  {16a}^{2} b -  \frac{ {a}^{2}b }{16}  \\  \frac{255}{16}  {a}^{2} b
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