Factorise 16a^2b - b ÷ 16a^2 ?
Yuvikabisla:
Nope, these are two different terms .....
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16a^2 b - b/16a^2
b(16a^2 - 1/16a^2)
b[ (4a)^2 - (1/4a)^2]
b(4a +1/4a) (4a - 1/4a)
b(16a^2 - 1/16a^2)
b[ (4a)^2 - (1/4a)^2]
b(4a +1/4a) (4a - 1/4a)
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