Factorise 16a 4 +54a
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29
2a(8a^3 + 27)
2a( (2a)^3 +(3)^3
2a( 2a +3) ( 4a^2 -6a + 9)
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2a( (2a)^3 +(3)^3
2a( 2a +3) ( 4a^2 -6a + 9)
mark me as a brainlist
Answered by
18
16a^4 + 54a
2 ( 8a^3 + 27)
2a (2a^3 + 3^3)
a^3+b^3 = (a+b) (a^2+b^2-ab)
2a (2a+3) (4a^2+9-6a)
(2a)(2a+3)(4a^2-6a+9)
2 ( 8a^3 + 27)
2a (2a^3 + 3^3)
a^3+b^3 = (a+b) (a^2+b^2-ab)
2a (2a+3) (4a^2+9-6a)
(2a)(2a+3)(4a^2-6a+9)
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