factorise 16a^4+54ab^3
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16a4 +54a =2a(8a3+27)
2a((2a)3+(3)3))
a3+b3=(a+b)(a2+b2-ab)
2a((2a+3)(4a2+9-6a)
=(2a) (2a+3)(4a2-6a+9)
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