Question

Factorise 16a^5 – 144a^3

Answer 1

Answer:

Given

$16a {}^{5} - 144a {}^{3} \\ = 16a {}^{3} (a {}^{2} - 9) \\ = 16a {}^{3}(a {}^{2} - 3 {}^{2} )$

We know

$(x {}^{2} - y {}^{2} ) = (x + y)(x - y) \\ here \: for \: (a {}^{2} - 3 {}^{2}) \\ x = a \: \: and y = 3 \\ so \\ 16a {}^{3}(a{ }^{2} - 3 {}^{2} ) \\ = 16a {}^{3}(a + 3)(a -3)$

Answer 2

16a^5 – 144a^3

• =16a
• 16a 5
• 16a 5 −144a
• 16a 5 −144a 3
• 16a 5 −144a 3
• 16a 5 −144a 3 =16a
• 16a 5 −144a 3 =16a 3
• 16a 5 −144a 3 =16a 3 (a
• 16a 5 −144a 3 =16a 3 (a 2
• 16a 5 −144a 3 =16a 3 (a 2 −9)
• 16a 5 −144a 3 =16a 3 (a 2 −9)=16a
• 16a 5 −144a 3 =16a 3 (a 2 −9)=16a 3
• 16a 5 −144a 3 =16a 3 (a 2 −9)=16a 3 (a
• 16a 5 −144a 3 =16a 3 (a 2 −9)=16a 3 (a 2
• 16a 5 −144a 3 =16a 3 (a 2 −9)=16a 3 (a 2 −3
• 16a 5 −144a 3 =16a 3 (a 2 −9)=16a 3 (a 2 −3 2
• 16a 5 −144a 3 =16a 3 (a 2 −9)=16a 3 (a 2 −3 2 )
• 16a 5 −144a 3 =16a 3 (a 2 −9)=16a 3 (a 2 −3 2 )
• 16a 5 −144a 3 =16a 3 (a 2 −9)=16a 3 (a 2 −3 2 )

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