Question

factorise 16a2 - 24bc-9b2-16 c2

Answer 1

Answer:

(4a+3b+4c)(4a-3b-4c)

Step-by-step explanation:

$16a^2-24bc-9b^2-16c^2=(4a)^2-(3b+4c)^2$

According to the identity $a^2-b^2=(a+b)(a-b)$,

the expression is factored into $(4a+3b+4c)(4a-3b-4c)$.

∴$(4a+3b+4c)(4a-3b-4c)$

Answer 2

This is your answer➡(4a+3b+4c)(4a-3b-4c)

Hope it helps you☺