Math, asked by bdebabrata837, 4 months ago

factorise 16a² - 9(b-3a)²​

Answers

Answered by shruti6166
0

Step-by-step explanation:

16a^2-9(b-3a)^2

16a^2-9((b) ^2-2(b)(3a) +(3)^2)

16a^2-9(b^2-6ab+9a^2)

16a^2-9b^2+54ab-81a^2

-65a^2-9b^2+54ab

65a^2+9b^2-54ab

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