Question

factorise . 16a² + 9b² + 4c² + 24ab +12bc+ 16ca.​

Answer 1

Step-by-step explanation:

16a²+9b²+4c²+24ab+12bc+16ca

[(a+b+c)²=a²+b²+c²+2ab+2bc+2ca]

(4a)²+(3b)²+(2c)²+2(4a)(3b)+2(3b)(2c)+2(2c)(4a)

(4a+3b+2c)²

hope it will help u

follow me

mark this answer as brain list

Answer 2

Please mark as Brainliest

Folow me

16a² + 9b² + 4c² + 24ab +12bc+ 16ca.

=(4a)^2+(3b)^2+(2c)^2+2(4a*3b)+2(3b*2c)+2(4a*2c)

=(4a+3b+2c)^2

Answer:---

(4a+3b+2c)^2