Question

Factorise 16a²-b²+4b-4



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Answer 1

Answer:

16 a^2-b^2+4b-4

=16a^2-(b^2-4b+4)

=(4a)^2-{(b)^2-2.b.2+(2)^2}

=(4a)^2-(b-2)^2

={4a+(b-2)}{4a-(b-2)}

=(4a+b-2)(4a-b+2)