Question

Factorise 16a2-b2-8a+2b​

Answer 1

Step-by-step explanation:

$16 {a}^{2} - {b}^{2} - 8a + 2b \\ = {(4a})^{2} - 2 \times 4a \times 1 + {1}^{2} - ( {b}^{2} - 2 \times b \times 1 + {1}^{2} ) \\ = {(4a - 1})^{2} - ( {b - 1})^{2} \\ = (4a - 1 + b - 1)(4a - 1 - b + 1) \\ =( 4a + b - 2)(4a - b)$

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