Question

Factorise 16a³ - 128/b³
Please help 8th standard.
Please answer the above question.​

Answer 1

Answer:

$16 {a}^{3} - \frac{128}{ {b}^{3} }$

$2(8{a}^{3} - \frac{64}{ {b}^{3} } )$

$2(( {2a)}^{3} - ( {\frac{4}{b}})^{3})$

a³-b³=(a-b)(a²+ab+b²)

using this we can factorise easily

Answer 2

Answer:

sorry mere baton ka aap galat mat samajhna