Math, asked by fidvizahra16, 1 day ago

Factorise 16a³ - 2/a³ + 6a - 3/a​

Answers

Answered by manaalmaple255
0

Step-by-step explanation:

STEP

1

:

3

Simplify —

a

Equation at the end of step

1

:

2 3

(((16•(a3))-————)+6a)-—

(a3) a

STEP

2

:

2

Simplify ——

a3

Equation at the end of step

2

:

2 3

(((16 • (a3)) - ——) + 6a) - —

a3 a

STEP

3

:

Equation at the end of step

3

:

2 3

((24a3 - ——) + 6a) - —

a3 a

STEP

4

:

Rewriting the whole as an Equivalent Fraction

4.1 Subtracting a fraction from a whole

Rewrite the whole as a fraction using a3 as the denominator :

24a3 24a3 • a3

24a3 = ———— = —————————

1 a3

Equivalent fraction : The fraction thus generated looks different but has the same value as the whole

Common denominator : The equivalent fraction and the other fraction involved in the calculation share the same denominator

Adding fractions that have a common denominator :

4.2 Adding up the two equivalent fractions

Add the two equivalent fractions which now have a common denominator

Combine the numerators together, put the sum or difference over the common denominator then reduce to lowest terms if possible:

24a3 • a3 - (2) 16a6 - 2

——————————————— = ————————

a3 a3

Equation at the end of step

4

:

(16a6 - 2) 3

(—————————— + 6a) - —

a3 a

STEP

5

:

Rewriting the whole as an Equivalent Fraction :

5.1 Adding a whole to a fraction

Rewrite the whole as a fraction using a3 as the denominator :

6a 6a • a3

6a = —— = ———————

1 a3

STEP

6

:

Pulling out like terms :

6.1 Pull out like factors :

16a6 - 2 = 2 • (8a6 - 1)

Trying to factor as a Difference of Squares:

6.2 Factoring: 8a6 - 1

Theory : A difference of two perfect squares, A2 - B2 can be factored into (A+B) • (A-B)

Proof : (A+B) • (A-B) =

A2 - AB + BA - B2 =

A2 - AB + AB - B2 =

A2 - B2

Note : AB = BA is the commutative property of multiplication.

Note : - AB + AB equals zero and is therefore eliminated from the expression.

Check : 8 is not a square !!

Ruling : Binomial can not be factored as the

difference of two perfect squares

Polynomial Roots Calculator :

6.3 Find roots (zeroes) of : F(a) = 8a6 - 1

Polynomial Roots Calculator is a set of methods aimed at finding values of a for which F(a)=0

Rational Roots Test is one of the above mentioned tools. It would only find Rational Roots that is numbers a which can be expressed as the quotient of two integers

The Rational Root Theorem states that if a polynomial zeroes for a rational number P/Q then P is a factor of the Trailing Constant and Q is a factor of the Leading Coefficient

In this case, the Leading Coefficient is 8 and the Trailing Constant is -1.

The factor(s) are:

of the Leading Coefficient : 1,2 ,4 ,8

of the Trailing Constant : 1

Let us test ....

P Q P/Q F(P/Q) Divisor

-1 1 -1.00 7.00

-1 2 -0.50 -0.88

-1 4 -0.25 -1.00

-1 8 -0.12 -1.00

1 1 1.00 7.00

1 2 0.50 -0.88

1 4 0.25 -1.00

1 8 0.12 -1.00

Polynomial Roots Calculator found no rational roots

Adding fractions that have a common denominator :

6.4 Adding up the two equivalent fractions

2 • (8a6-1) + 6a • a3 16a6 + 6a4 - 2

————————————————————— = ——————————————

a3 a3

Equation at the end of step

6

:

(16a6 + 6a4 - 2) 3

———————————————— - —

a3 a

STEP

7

:

STEP

8

:

Pulling out like terms :

8.1 Pull out like factors :

16a6 + 6a4 - 2 = 2 • (8a6 + 3a4 - 1)

Polynomial Roots Calculator :

8.2 Find roots (zeroes) of : F(a) = 8a6 + 3a4 - 1

See theory in step 6.3

In this case, the Leading Coefficient is 8 and the Trailing Constant is -1.

The factor(s) are:

of the Leading Coefficient : 1,2 ,4 ,8

of the Trailing Constant : 1

Let us test ....

P Q P/Q F(P/Q) Divisor

-1 1 -1.00 10.00

-1 2 -0.50 -0.69

-1 4 -0.25 -0.99

-1 8 -0.12 -1.00

1 1 1.00 10.00

1 2 0.50 -0.69

1 4 0.25 -0.99

1 8 0.12 -1.00

Polynomial Roots Calculator found no rational roots

Calculating the Least Common Multiple :

8.3 Find the Least Common Multiple

The left denominator is : a3

The right denominator is : a

Number of times each Algebraic Factor

appears in the factorization of:

Algebraic

Factor Left

Denominator Right

Denominator L.C.M = Max

{Left,Right}

a 3 1 3

Least Common Multiple:

a3

Calculating Multipliers :

8.4 Calculate multipliers for the two fractions

Denote the Least Common Multiple by L.C.M

Denote the Left Multiplier by Left_M

Denote the Right Multiplier by Right_M

Denote the Left Deniminator by L_Deno

Denote the Right Multiplier by R_Deno

Left_M = L.C.M / L_Deno = 1

Right_M = L.C.M / R_Deno = a2

Making Equivalent Fractions :

8.5 Rewrite the two fractions into equivalent fractions

Two fractions are called equivalent if they have the same numeric value.

For example : 1/2 and 2/4 are equivalent, y/(y+1)2 and (y2+y)/(y+1)3 are equivalent as well.

L. Mult. • L. Num. 2 • (8a6+3a4-1)

—————————————————— = ———————————————

L.C.M a3

R. Mult. • R. Num. 3 • a2

—————————————————— = ——————

L.C.M a3

2 • (8a6+3a4-1) - (3 • a2) 16a6 + 6a4 - 3a2 - 2

—————————————————————————— = ————————————————————

a3 a3

Final result :

16a6 + 6a4 3a2 - 2

————————————————————

a3

Answered by Sayalizodgekar
0

Answer:

16a³- 1 . 2/a³+6a - 1 . 3/a

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