factorise 16a³-2/a³+6a-3/a
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Answer:
a = 2^1/3 - 2^(-1/3)
a + 2^(-1/3)= 2^1/3…………………(1(
On cubing both sides
a^3 +3.a.2^(-1/3)(a+2^(-1/3)+ 2^-1 =2
putting {a+ 2^(-1/3)}=2^1/3 from eq (1).
a^3+3.a.2^(-1/3)(2^1/3) +1/2= 2
or 2a^3+6a +1 =4
or 2a^3+6a - 3 = 0 , Answer
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