Question

factorise 16a³-4a it's urgent​

Answer 1

Answer:

according to question :-

16a^3 - 4a

4a (4a^2 - 1)

4a [(2a) ^2 - 1^2]

4a (2a+1) (2a-1)

hope you understand plz thank my answer

Answer 2

$16 {a }^{3} - 4a \\ \\ 4a(4 {a}^{2} - 1) \\ \\ (4a)(4 {a}^{2} - 1)$

hope it helps u....