Factorise:- 16a4 - 54a
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Step-by-step explanation:
16a^4 - 54a
= a(16a^3-54)
= 2a(8a^3-27)
= 2a{(2a)^3-(3)^3}
= 2a{(2a-3)^3 + 3(2a)(3)(2a-3)}
= (2a)(2a-3){(2a-3)^2 + 18a }
= a(4a-6)(4a^2+9-12a+18a}
= a(4a-6)(4a^2+6a+9)
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