Factorise: 16c⁴ − 1
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Solution:
Topic: Factorisation.
We have to factorise - 16c⁴ - 1.
- This problem can be solved using identity - a² - b² = (a + b)(a - b)
- We have to express the given polynomial as a difference of two squares and then using the above mentioned identity, we will factorise.
Solution:
16c⁴ - 1 can be written as,
= (4c²)² - (1)²
Applying the identity here, we get,
= (4c² + 1)(4c² - 1)
4c² - 1 can be written as,
= (2c)² - (1)²
Applying the same identity again, we get,
= (2c + 1)(2c - 1)
So,
→ 4c² - 1 = (2c + 1)(2c - 1)
So,
16c⁴ - 1
= (4c² + 1)(4c² - 1)
= (4c² + 1)(2c + 1)(2c - 1) which is our required answer.
Answer:
- (4c² + 1)(2c + 1)(2c - 1)
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