Question

factorise 16pq+8+4q+32p

Answer 1

Step-by-step explanation:

Area of a rectangle = Length x breath

Breadth = b cm

Length = (b+ 18) cm ( according to the condition of the problem)

Let the Area be ‘ A' cm^2

(b+18)(b) = A

b^2+ 18b = A (1)

New length = b+ 18+6 =( b+24)cm

New breadth = b + 6 cm

New area =( A+ 168) cm^2

(b+24)(b+6) = A+168.

b^2+ 30b + 144 = A+168 (2)

Subtraction eq(1) - eq(2)

12 b +144 = 168 (b^2 & A cancelled)

12b = 168–144

12b = 24

b = 2cm

Breadth = 2cm.

Length = 18+ 2= 20 cm

Verification LB = 20x2= 40 cm^2

(18+6)(6+2) = 24 x 8 = 208 cm^2

So the new area is increased by 168 cm^2 (verified)

Ans: Length is 20 cm & breadth is 2 cm.

Answer 2

Answer: 4(4p+1) (q+2)

Step-by-step explanation:

16pq + 8 + 4q + 32p

4(4pq+2+q+8p)

4(4pq+q) + (2+8p)

4.q(4p+1) + 2(

4(4p+1) (q+2)