Factorise: 16x^4-y^4
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16x^4-y^4
(4x^2)^2-(y2)^2 [a^2-b^2=(a+b)(a-b)]
(4x^2-y^2)(4x^2+y^2)
[(2x)^2-y^2](4x^2+y^2) [a^2-b^2=(a+b)(a-b)]
(2x-y)(2x+y)(4x^2+y^2)
Hope it helps you!!!
(4x^2)^2-(y2)^2 [a^2-b^2=(a+b)(a-b)]
(4x^2-y^2)(4x^2+y^2)
[(2x)^2-y^2](4x^2+y^2) [a^2-b^2=(a+b)(a-b)]
(2x-y)(2x+y)(4x^2+y^2)
Hope it helps you!!!
Answered by
0
Answer:
16x^4-y^4
(4x^2)^2-(y2)^2 [a^2-b^2=(a+b)(a-b)]
(4x^2-y^2)(4x^2+y^2)
[(2x)^2-y^2](4x^2+y^2) [a^2-b^2=(a+b)(a-b)]
(2x-y)(2x+y)(4x^2+y^2)
Step-by-step explanation:
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