factorise 16x sq - 24xy sq + 9y sq - 4x + 3y
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Answered by
1
Answer:
Step-by-step explanation:
16x²-24xy+9y²-4x+3y
And
16x²-24xy+9y² Can be a formula of (4x-3y)²
Then,
(4x-3y)²-4x+3y
(4x-3y)²-(4x-3y)
Taking 4x-3y common
We get,
(4x-3y)[(4x-3y)-1]
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Answered by
3
Answer:
16x² - 24xy + 9y² - 4x + 3y
=[(4x²) - 2(4x)(3y) + (3y) ²] - 4x + 3y
=(4x-3y) ² - 4x + 3y
=[(4x - 3y) (4x -3y)] - 1 (4x - 3y)
=(4x - 3y) (4x - 3y -1)
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