Question

factorise:16x²-(2y-3z)²​

Answer 1

Step-by-step explanation:

Given

16x^2 - ( 2y - 3z )

Find :

Factories 16x^2 ( 2y - 3z )

Solution :

Using identities

a^2 - b^2 = ( a + b ) ( a - b )

Putting Value in identities

( 4x ) ^2 - ( 2y - 3z ) ^2

= ( 4x + 2y - 3z ) ( 4x - 2y + 3z )

= 16x^2 - ( 2y - 3z ) ^2

The Factories is 16x^2 - ( 2y - 3z ) ^2

Answer 2

Answer:

Step-by-step explanation:

$16 x^{2} -(2 y-3 z)^{2} \\:(x-y)^{2} =x^{2} -2 xy+y^{2} \\16 x^{2} -((2y)^{2} -2*2y*3z+(3z)^{2} \\16x^{2} -(4y^{2} -12yz+9z^{2} )\\16x^{2} -(4y^{2} -6yz-6yz+9z^{2} )\\16x^{2} -(2y(2y-3z)-3z(2y-3z)\\16x^{2} -(2y-3z)(2y-3z)\\16x^{2} -(2y-3z)^{2}$

Hope ,it helpful for u