Question

factorise 16y²-40y+25​

Answer 1

Answer:

16 y^2-40y+25

=(4y)^2-2.4y.5+(5)^2

=(4y-5)^2

Answer 2

${\pmb{\sf{\underline{Required \; Solution...}}}}$

➼ Factorise the following expression -

⠀⠀⠀⠀⠀${\sf{16y^{2}-40y+25}}$

➼ It is given that we have to factorise the given expression. Let us factorise this properly by using suitable identity.

➼ Suitable identity is given below to solve all the following expressions -

${\small{\underline{\boxed{\sf{\bigstar \: \: a^{2} - 2ab + b^{2} \: = (a-b)^{2}}}}}}$

➼ Now let us solve this part properly! Full Solution is given below!

${\sf{:\implies 16y^{2}-40y+25}}$

${\sf{:\implies a^{2} - 2ab + b^{2}}}$

~ 4 into 4 is equal to 16 and 4 sq. is also 16. It is same. Henceforth, according to the identity let us carry on!

${\sf{:\implies a^{2} - 2ab + b^{2}}}$

${\sf{:\implies (4y)^{2} - 2(20)(y) + 5^{2}}}$

${\sf{:\implies (4y)^{2} - 2(20y) + 5^{2}}}$

${\sf{:\implies (4y)^{2} - 40y + 5^{2}}}$

${\sf{:\implies (a-b)^{2}}}$

~ Here, a is 4y and b is 5.

${\sf{:\implies (4y-5)^{2}}}$

⠀⠀⠀⠀⠀⠀⠀⠀⠀Hence, factorised!