factorise 16ypower2-121
Answers
Answered by
0
Rewrite
16
x
2
as
(
4
x
)
2
.
(
4
x
)
2
−
121
Rewrite
121
as
11
2
.
(
4
x
)
2
−
11
2
Since both terms are perfect squares, factor using the difference of squares formula,
a
2
−
b
2
=
(
a
+
b
)
(
a
−
b
)
where
a
=
4
x
and
b
=
11
.
(
4
x
+
11
)
(
4
x
−
11
)
Answered by
1
Answer:
(4y + 11) (4y - 11)
Step-by-step explanation:
Given,
16y² - 121
Writing in terms of power:
= (4y)² - (11)²
Using identity a² - b² = (a + b) ( a - b)
= (4y + 11) (4y - 11)
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