Factorise -16z+20z³ using common factorisation.
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Answered by
6
-16z + 20z^3
= 20z^3 - 16z
Take 4z common
= 4z × ( 5z^2 - 4 )
= 4z × ( 5z^2 + ( 2 √5 )z - (2√5 )z - 4 )
= 4z × ( √5z × ( √5z + 2 ) - 2 × ( √5z + 2 ) )
= ( 4z ) ( √5z + 2 ) ( √5z - 2 )
= 20z^3 - 16z
Take 4z common
= 4z × ( 5z^2 - 4 )
= 4z × ( 5z^2 + ( 2 √5 )z - (2√5 )z - 4 )
= 4z × ( √5z × ( √5z + 2 ) - 2 × ( √5z + 2 ) )
= ( 4z ) ( √5z + 2 ) ( √5z - 2 )
Answered by
4
Answer:
Step-by-step explanation:
First we'll take each term's factors:
-16z= -2×2×2×2×z
20z^3=2×2×5×z×z×z
The common factors are=4×z=4z
So we'll take 4z outside the bracket
4z(-4+5z^3)
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