Question

Factorise
180(3a-4b)^2-405(4a-3b)^2​

Answer 1

Answer

$(3a+4b)×(4a+3b)$

$3a(4a+3b)+4b(4a+3b)$

$⇒12a^2+9ab+16ab+12b^2$

$⇒12a^2+25ab+12b^2$

$⇒12[a^2+b^2−2ab]+ab$

$=12[a+b]^2+ab$

hope this will help you...

Answer 2

Answer

$(3a+4b)×(4a+3b)$

$3a(4a+3b)+4b(4a+3b)$

$⇒12a2+9ab+16ab+12b2$

$⇒12a2+25ab+12b2$

$⇒12[a2+b2−2ab]+ab$

$=12[a+b]2+ab$

hope this will help you...