factorise 18a*a-50 using appropriate identites
Answers
Answered by
15
18a² - 50
=> 2(9a² - 25)
=> 2[ (3a)² - (5)²]
By formula, a² - b² = (a+b) (a -b)
Here,
=> 2(3a - 5)(3a + 5)
=> (2)(3a - 5)(3a + 5)
I hope this will help you
(-:
=> 2(9a² - 25)
=> 2[ (3a)² - (5)²]
By formula, a² - b² = (a+b) (a -b)
Here,
=> 2(3a - 5)(3a + 5)
=> (2)(3a - 5)(3a + 5)
I hope this will help you
(-:
Answered by
8
18a×a - 50

Using following identity

Using following identity
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