factorise 18y^2-12y+2
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Answer:
i have done it in the attachment
process used: middle term factorisation
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Answer:
y = 1
Explanation:
18y^2-12y+2 = 0
Reduce the equation by 2
9y^2-6y+1 = 0
Product = 9y^2
Sum = -6y
9y^2-3y-3y+1 = 0
Take common,
3y(y-1)-3(y-1) = 0
(3y-3)(y-1) = 0
(3y-3) = 0
3y = 3
y = 3/3
y = 1
(y-1) = 0
y = 1
Therefore:
y=1, y=1
Hope this helps!
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