Math, asked by anjusingh0208, 11 months ago

Factorise: 19m² + 40mn - 59n²​

Answers

Answered by omprakashmalviya2000
1

Answer:

(m - n)(19m + 59n).

Step-by-step explanation:

19m^2 + 40mn - 59n^2

{Splitting the middle term, we get.}

→19m^2 + (59 - 19)mn - 59n^2

{We can see that the product of co-effients of first and third term (19 × -59 = -1121) is equal to the splited coefficients of middle term (-19 × 59 = -1121), so we can factorize it further.}

→19m^2 + 59mn - 19mn - 59n^2

→m(19m + 59n) + n(-19m - 59n)

→m(19m + 59n) - n(19m + 59n)

→(m - n)(19m + 59n)

{Hope it helped you...}

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