factorise 1a3+b3+125c3-15abc
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Question :-
➠ a³ + b³ + 125c³ - 15abc
Formula used :-
➪ a³ + b³ + c³ - 3abc
➭ (a + b + c) (a² + b² + c² - ab - bc - ac)
Answer :-
➠ a³ + b³ + 125c³ - 15abc
➻ (a)³ + (b)³ + (5c)³ - 3 × a × b × 5c
➻ (a + b + 5c) {(a)² + (b)² + (5c)² - a × b - b × 5c - a × 5c }
➻ (a + b + 5c) (a² + b² + 25c² - ab - 5bc - 5ac)
∴ The value of a³ + b³ + 125c³ - 15abc is (a + b + 5c) (a² + b² + 25c² - ab - 5bc - 5ac)
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