Question

factorise 1y²—1y—12 factor theorem.​

Answer 1

Step-by-step explanation:

Given that,

y²-y-12 is the polynomial p(x)

let, p(x)=y²-y-12=0

y²-4y+3y-12=0                  (∵ -12 factors are 3 & -4 to split '-y' )

⇒y(y-4)+3(y-4)=0

⇒(y+3)(y-4)=0

case-(1):                   case-(2):

   ⇒y+3=0                    ⇒y-4=0

   ⇒y=-3                         ⇒y=4

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Answer 2

Answer:

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