Math, asked by AyushLodh, 9 months ago

factorise (2^2-2x)^2-5(2^-2)-y(x^2-2x)​

Answers

Answered by nisthasaini22
1

Answer:

(2²-2x)²-5(2²-2)-y(x²-2x)

2(4-2x)-5(4-2)-y(x²-2x)

8-2x-20+10-yx²+2xy

-20+10+8-2x-yx²+2xy

-2-2x-yx²+2xy

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